Pb(NO3)2 0.16M: Molar Concentration of Ions

[AJKing]

Homework Statement

What molar concentration of each ion appear in 0.16M Pb(NO₃)₂?

*Note* The title incorrectly says "moles".

Homework Equations

M = mol/L

The Attempt at a Solution

My teacher tells me this is wrong, but I can't see my fault:

Molar Mass of Pb⁺² = 207.20g
Molar Mass of NO₃^- = 124.02g

$\frac{x}{1L} = 0.16M$

$x = 0.16mol$

$0.16mol = \frac{y*1mol}{331.22g}$

$y = 53g$$Pb: 53g * \frac{207.20g}{331.22g} = 33g$

$\frac{33g}{331.22g} = 0.10mol$$NO_{3}: 53g *\frac{124.02}{331.22g} = 20g$

$\frac{20g}{331.22g} = 0.06mol$$Pb = \frac{0.10mol}{1L} = 0.10M$

$NO_{3} = \frac{0.06mol}{1L} = 0.06M$

Any ideas where I messed up?
Or if I did?

 

[AJKing]

I would also like to say that in my first attempt to solve this, I simply multiplied 0.16M by the fractions of mass for lead and nitrate and got the same answers.

That was the "incorrect" version. This is my third attempt, with the same results.