PDF of Order Statistics for RVs: \gamma_1,\,\ldots,\,\gamma_M

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SUMMARY

The discussion focuses on deriving the probability density function (PDF) for the largest m order statistics from a set of independent and identically distributed random variables (RVs) denoted as \(\gamma_1, \gamma_2, \ldots, \gamma_M\). The PDF for the largest order statistic, \(f_{\gamma_{1:M}}(\gamma)\), is established using the cumulative distribution function (CDF) \(F_{\gamma}(\gamma)\) of the original RVs, leading to the formula \(f_{\gamma_{1:M}}(\gamma) = \frac{d}{d\,\gamma}\left[F_{\gamma}(\gamma)\right]^M\). The discussion also highlights the challenge of deriving the PDF for the m-th largest order statistics, indicating a need for deeper understanding of the underlying statistical principles.

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EngWiPy
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Hello,

Suppose that we have the following set of independent and identically distributed RVs: [tex]\gamma_1,\,\gamma_2,\,\ldots,\,\gamma_M[/tex]. Arranging them in descending order as: [tex]\gamma_{1:M}\ge\gamma_{2:M}\ge\cdots\ge\gamma_{M:M}[/tex]. Now suppose we select the largest [tex]m\leq M[/tex] order statistics. What is the PDF of the selected set? Mathematically:

[tex]f_{\gamma_{1:M},\,\ldots,\,\gamma_{m:M}}(\gamma_{1:M},\,\ldots,\,\gamma_{m:M})=??[/tex]

Thanks in advance
 
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What would f be for m = 1? How do you get there?
 
EnumaElish said:
What would f be for m = 1? How do you get there?

[tex]f_{\gamma_{1:M}}(\gamma)=\frac{d}{d\,\gamma}F_{\gamma_{1:M}}(\gamma)=\frac{d}{d\,\gamma}\text{Pr}\left[\gamma_{1:M}\le\gamma\right]=\frac{d}{d\,\gamma}\text{Pr}\left[\gamma_{1}\le\gamma,\gamma_{2}\le\gamma,\ldots,\gamma_{M}\le\gamma\right]=\frac{d}{d\,\gamma}\left[F_{\gamma}(\gamma)\right]^M[/tex]

where [tex]F_{\gamma}(\gamma)[/tex] is the CDF of the original set of RVs.

But when we pick a subset of the [tex]m^{\text{th}}[/tex] largest order statistics, how can we treat the statistics? I mean I have the final answer from books and papers, but I didn't understand how they derive it.
 

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