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Pencil tipping problem - trying to understand uncertainty

  1. Oct 26, 2009 #1
    Greetings, I'm new to the forums and just starting grad school. We recently had a homework problem to estimate the amount of time a pencil could stand on its tip without falling over. I remember an undergrad professor mentioning that he had been asked this problem on his orals so perhaps it is common and some of you have seen it before.

    In any case, the desired solution was to first solve for the classical equations of motion and then plug in initial conditions based on the uncertainty principle. You assume minimum uncertainty, assume that values of [tex]\dot\theta[/tex] and [tex]\theta[/tex] are approximately equal to their variances, and then optimize the ratio of [tex]\dot\theta[/tex] and [tex]\theta[/tex] to maximize the time before it falls over. This method yields something on the order of a few seconds.

    The superficial problem that I have with this is that [tex]\dot\theta[/tex] and [tex]\theta[/tex] are both assumed to be positive. I'm alright with approximating it as one dimensional and saying that [tex]\dot\theta[/tex] and [tex]\theta[/tex] will be on order of [tex]\sigma[tex] away from their centers (in this case 0), but shouldn't it be equally likely that they have opposite sign as positive sign? If they had opposite sign and you maximized the time it took for the pencil to fall based on the classical equations it would be infinite.

    The deeper problem I have is that I don't understand how you can just put the uncertainty in the initial conditions. I'm trying to understand how uncertainty effects time evolution, but I'm up against a wall here. I could almost see something like drawing values of p and x from under their distributions, evolving them classically for some small time, drawing new values from their distributions, etc. I know that that isn't correct, but is there any way remotely like this to think about it?

    Most of the course so far has been devoted to pure math and we're only just starting to see anything remotely physical now. Sorry if my question is naive but I would really appreciate any insight that anyone has to offer.

    Thanks.
     
  2. jcsd
  3. Oct 27, 2009 #2
    Very confusing to use half-QM and half mechanics to solve this, especially since in my mind the uncertainty principle is not extremely well demonstrated like other parts of the theory. How you can obtain some sort of time scale from the position/momentum principle is beyond me!
     
  4. Oct 28, 2009 #3
    I remember the pencil-tipping problem very well. The answer is about XX seconds. In the uncertainty principle, δx and δp (or δθ and δθ-dot) are conjugate coordinates, and have no inherent correlation. In addition, δx and δp should be treated as rms (root mean square) uncertainties, meaning that they are inherently positive quantities. So treat δx and δp as initial conditions, and use classical mechanics to calculate the tipping time.
    Bob S
     
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