Percent Change Of current when the switch is closed

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SUMMARY

The discussion centers on calculating the percent change in current when a switch is closed in a circuit involving a 1.50 V battery with an internal resistance of 0.30 Ω and a bulb resistance of 8.00 Ω. The user attempts various calculations for percent change but finds discrepancies in the results. The correct approach involves understanding the impact of internal resistance on current flow, which affects the brightness of the bulb when the switch is closed. A circuit diagram is requested to clarify the setup.

PREREQUISITES
  • Understanding of Ohm's Law
  • Familiarity with circuit analysis concepts
  • Knowledge of internal resistance in batteries
  • Ability to calculate percent change in electrical parameters
NEXT STEPS
  • Study circuit analysis techniques using Kirchhoff's laws
  • Learn about the effects of internal resistance on circuit performance
  • Explore the concept of equivalent resistance in series and parallel circuits
  • Review methods for calculating percent change in electrical measurements
USEFUL FOR

Electrical engineering students, hobbyists building circuits, and anyone interested in understanding the effects of internal resistance on circuit behavior.

ChrisWM
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Homework Statement
By what percent does the current through A change when the switch is closed?

I found the value of the current to be .174 A when the switch is closed and value of the current when the switch is open to be .181 A.
Relevant Equations
final-initial/initial
(.174A-.181A)/.181A=-3.86% but it says it wrong, and I did (.181A-.174A)/.174A =4.02% but this was wrong too. I've tried 3.87%,3.86%,-3.87%,-3.67%,4.02%, and -4.02% but all were wrong. I'm really not sure what to do here.
 
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Is there a circuit diagram?
 
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1590556060734.png
Here you go!
 
Here is the actual problem; For an ideal battery (r = 0 Ω), closing the switch in (Figure 1)does not affect the brightness of bulb A. In practice, bulb A dims just a little when the switch closes. To see why, assume that the 1.50 V battery has an internal resistance r = 0.30 Ω and that the resistance of a glowing bulb is R = 8.00 Ω.
 

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cnh1995 said:
Is there a circuit diagram?
 

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