MHB Did I Calculate the Perimeter of A Sector Correctly?

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The discussion revolves around calculating the perimeter of a sector with a radius of 5 inches and an angle of 30°. The initial calculation yielded a perimeter of 10.05 inches, which was incorrect. The correct formula involves converting the angle to radians and applying it properly, resulting in a perimeter of 12.62 inches. The error was identified in the computation method used for the angle conversion. The final confirmation shows that the correct perimeter is indeed 12.62 inches.
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A sector has the following:

radius = 5 inches

angle = 30°

I was told to use the formula in the picture.

My answer is P = 10.05 inches.

The book's answer is P = 12.62 inches.

Am I using the right formula?

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RTCNTC said:
A sector has the following:

radius = 5 inches

angle = 30°

I was told to use the formula in the picture.

My answer is P = 10.05 inches.

The book's answer is P = 12.62 inches.

Am I using the right formula?

It looks like you have performed this computation: $(2 \pi / 360) (30)(2\pi / 360)(5) + (2)(5)$ instead of $(2 \pi / 360) (30)(5) + (2)(5)$

Remember: $\theta$ in degrees is equal to $\theta \cdot \dfrac{2\pi}{360}$ (or simply $\theta \cdot \dfrac{\pi}{180}$) in radians.
 
I converted 30° to radians before using the formula. This was my error.

P = (30/360) • (2π)(5) + 2(5)

P = (1/12)((10π) + 10

P = 12.62 inches

I got it.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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