Permutation and combination problem

In summary, the conversation discusses the question of how many ways 3 balls can be chosen from a box containing 8 balls, with 3 being similar and the rest being different, if the order of picking out the balls is not important. The conversation goes into detail about the various possibilities and combinations, ultimately coming to the conclusion that there are 26 ways to choose the 3 balls.
  • #1
aerosmith
10
0
i recently had my A levels exam and was stuck at a question

there are 8 balls in a box, 3 are similar and the rest are different, how many ways can 3 balls be chosen if the order of picking out the balls is not important

its worth 4 marks, and i do not know where to start even.:frown:
 
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  • #2
Consider the following: in how many possibilities do the similar balls appear?

Say only ball 1 appears in spot 1 (ball 2 and 3 do not appear), you have (8-3)*(8-4) = 20 possibilities of the sort. Now say ball 1 appear in spot 2, you still have 20 possibitities. Now it's easy to see why the total number of possibilties is 3*20 = 60. Now consider ball 2 and 3. You have for each 60 possibities. However since ball 1, 2 and 3 are similar, all the possibilities that occur for ball 2 and 3 have equivalents in the possibilities for ball 1, thus we only take 60 into account.

Next, use the same procedure for 2 balls appearing:In how many ways can 2 balls be rearanged with 3 spots? The awnser is 3*2 = 6. For the remaning spot, how many possibilities can you have? The awnser is 8-3 = 5. Now with using combinations, the number of possibilities is 6*5 = 30. Now since we are considering 2 balls, we are dealing with reoccuring possibilities (i.e. ball 1 inversed with ball 2 etc.). The question is, if there's 2 balls, in how many ways can they be interchanged? The awnser is simply 2*1 = 2. Since we do not wish to have reoccurences, we devided 30 by 2, giving 15.

We then consider the 3 similar balls showing up. It should be obvious that this account for only 1 possibility.

Now we have 60 + 15 + 1 = 76 as the final awnser.
 
  • #3
thanks

thanks for the reply, but i thought the order did not matter? why would it be 20*3 and not just 20 since order does not matter.
 
  • #4
Hummm... yeah true, since it says the order dosen't count, it's 20. For 2 balls, since the order dosen't count it's only 5... so the final awnser should be 26.
 
  • #5
thanks

thats what i thought too...but... if you look closer at the question, it says the order the ball was picked does not matter, that does not mean the order it will be after all 3 were picked did not matter, am i right to say that?
 
  • #6
Ways of choosing 3 balls from eight : (8,3)
Ways of choosing 3 balls from eight when three are the same : (8,3)/3!
8!/5!(3!)^2 =336/36

Probably not right, just posting my thoughts.
 
  • #7
acm said:
Ways of choosing 3 balls from eight : (8,3)
Ways of choosing 3 balls from eight when three are the same : (8,3)/3!
8!/5!(3!)^2 =336/36

Probably not right, just posting my thoughts.

How can you have non-integer number of possibilities? :-p
 
  • #8
aerosmith said:
thats what i thought too...but... if you look closer at the question, it says the order the ball was picked does not matter, that does not mean the order it will be after all 3 were picked did not matter, am i right to say that?

I think 26 is the correct anwnser... If they specify that the order dosen't count, it means that different arrangements for the same balls are neglected.
 

Related to Permutation and combination problem

1. What is the difference between permutation and combination?

Permutation and combination are both ways of arranging a set of elements. However, permutation is concerned with the order in which the elements are arranged, while combination is not. In other words, in permutation, the order matters, while in combination, the order does not matter.

2. How do I know when to use permutation or combination in a problem?

The key difference between permutation and combination is whether the order matters or not. If the problem involves arranging objects in a specific order, then permutation should be used. If the problem only requires selecting a group of objects without regard to the order, then combination should be used.

3. What is the formula for calculating permutations?

The formula for calculating permutations is n! / (n-r)! where n is the total number of objects and r is the number of objects being arranged in a specific order. This is also known as the permutation formula.

4. What is the formula for calculating combinations?

The formula for calculating combinations is n! / (r!(n-r)!) where n is the total number of objects and r is the number of objects being selected. This is also known as the combination formula.

5. Can you give an example of a real-life application of permutation and combination?

One example of a real-life application of permutation and combination is in creating unique passwords. The order of the characters matters, so permutation is used to calculate the number of possible combinations for a password with a specific length and character set. Another example is in lottery games, where the order of the numbers matters, so permutation is used to determine the odds of winning. Combination can be used in situations such as choosing a committee from a group of people, where the order of selection does not matter.

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