Permutations and Combinations Problem

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SUMMARY

The problem of selecting one or more letters from the word "INSIPIDITY" involves understanding permutations and combinations, particularly with repeated elements. The correct approach to solve this problem is to utilize the formula ((4+1)(1+1)^6) - 1, which accounts for the independent choices of letters, including the repetitions of 'I'. The discussion highlights the importance of recognizing distinct scenarios to avoid over-counting, as demonstrated in the initial miscalculation. Mastery of these concepts requires practice and familiarity with combinatorial techniques.

PREREQUISITES
  • Understanding of permutations and combinations
  • Familiarity with combinatorial counting principles
  • Knowledge of handling repeated elements in combinations
  • Basic algebra for manipulating equations
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  • Study the combinatorial formula for counting selections with repetitions
  • Learn about the binomial theorem and its applications in combinatorics
  • Practice problems involving permutations and combinations with repeated elements
  • Explore generating functions as a method for solving combinatorial problems
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Students studying combinatorics, educators teaching mathematical concepts, and anyone looking to improve their problem-solving skills in mathematics.

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Homework Statement


In how many ways is it possible to select one or more letters from those in INSIPIDITY?


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The Attempt at a Solution


My initial impression was that this was a combinations problem and I did not have to take into account the repetitions. This led me to over-count because I had counted combinations like SIPI multiple times as SI2PI3 and SI1PI4 are indistinguishable. The only method I could think of was for each number of selected letters to add up the mutually exclusive scenarios that constituted it, as follows

1 letter selected: no I involved, 1 I involved
2 letters selected: no I's involved, 1 I involved, 2 I's involved
3 letters selected: no I's involved, 1 I involved, 2 I's involved, 3 I's involved etc.

Apparently ((4+1)(1+1)^6) -1 is a much quicker solution, however I am unable to interpret the logic of this solution. Could someone please explain it to me? Also if anyone could offer some tips on how to tackle these problems I would appreciate it, I have found this to be the most difficult subject I have encountered so far, mainly because there doesn't seem to be a procedure to follow like there was for calculus.
 
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You can take (0, 1, 2, 3 or 4) letters "I" -> 4+1 options
You can take (0 or 1) letters "N" -> ...
...
All those choices are independent of each other.

mainly because there doesn't seem to be a procedure to follow like there was for calculus.
There are always many ways to find a solution, the more ways you know and recognize (needs practice!) the easier it is to find a good one.
 
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Thanks for the help.
 

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