The discussion revolves around calculating the number of possible license plate combinations using a mix of letters and digits. Participants are exploring the implications of different interpretations of the problem statement, particularly regarding the inclusion of specific digits and letters.
There is an ongoing exchange of ideas, with some participants clarifying their understanding and others providing insights into potential misinterpretations. While multiple perspectives are being explored, no consensus has been reached on the correct approach.
Some participants note that certain letters may not appear on standard license plates in specific regions, which could affect the total count of valid combinations. This raises questions about the assumptions made in the problem statement regarding the character set.
That was an additional assumption/restriction on your part, not one that was given in the problem statement, and one that likely would have led to an incorrect answer.DaveC426913 said:
Yes.DaveC426913 said:
Or not...DaveC426913 said:
No, there is no mention whatsoever in the problem statement (which I quoted several posts back) about any non-conventional letter sets or any restrictions other than three letters followed by three digits.DaveC426913 said:
You are double counting some of the numerics. E.g. you are counting 112 as an example of x12 and as an example of 1x2.requied said:
So the answer became 36.504haruspex said:
Yes.requied said:
I guess there is no a similar application at letters order.haruspex said:
Quite so, that was easier. Had you only been told there was at least one A then, depending on your approach, there would have been a risk of double counting.requied said:
