PH of a mixed solution: is this right?

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SUMMARY

The final pH of a solution obtained by mixing 200 ml of 0.400 M NH3 with 300 ml of 0.100 M HCl is calculated to be 9.68 using an ICE table. The discussion confirms that when there is an excess of HCl, the pH can be determined using the equation pH = -log[H3O+]. It is also clarified that using two ICE tables is unnecessary in this scenario, as the dominant reaction involves the neutralization of NH3 by HCl.

PREREQUISITES
  • Understanding of acid-base reactions and neutralization.
  • Familiarity with ICE tables for equilibrium calculations.
  • Knowledge of pH and pOH concepts.
  • Basic grasp of Kb and Ka relationships in weak acids and bases.
NEXT STEPS
  • Study the calculation of pH for weak acid and strong base mixtures.
  • Learn about the Henderson-Hasselbalch equation for buffer solutions.
  • Explore the concept of pKa and its relation to pH in weak acid-base systems.
  • Investigate the use of multiple ICE tables in complex acid-base equilibria.
USEFUL FOR

Chemistry students, educators, and anyone involved in acid-base chemistry or solution preparation will benefit from this discussion.

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Homework Statement



What is the final pH of a solution obtained by mixing 200 ml of 0.400 M NH3 with 300 ml of 0.100 M HCl? (Kb = 1.8 x 10^-5)

Homework Equations



The Attempt at a Solution



I used an ICE table and came up with 9.68. Is that correct?

Should I have used two ICE tables instead of one? The first in the one direction and the second going back in the other direction?
 
Last edited:
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hint: the first reactions is that with NH3 and HCl, if you have excess HCl, then you can simply use the pH equation (pH= -log[H3O+]) to find the resulting pH, if the base is the excess, then the Kb equation is going to be used to determine the [OH-] concentration, and eventually the pH.
 
Thank you.
 

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