PH of a polyprotic acid using multiple equilibria - is this correct?

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SUMMARY

The discussion focuses on calculating the pH of 0.02025 M tartaric acid using multiple equilibria, specifically addressing the dissociation constants Ka1 (9.2 x 10-4) and Ka2 (4.31 x 10-5). The correct pH value determined is 2.41, which must be achieved through accurate calculations that consider all intermediate species, including HT-. Participants emphasize that neglecting intermediate reactions can lead to incorrect results, highlighting the importance of a thorough equilibrium analysis.

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  • Understanding of polyprotic acids and their dissociation.
  • Familiarity with equilibrium constants (Ka1 and Ka2).
  • Knowledge of pH calculations and the Henderson-Hasselbalch equation.
  • Ability to perform equilibrium calculations using multiple equilibria.
NEXT STEPS
  • Study the step-by-step equilibrium method for polyprotic acids.
  • Learn about the impact of intermediate species in acid-base equilibria.
  • Explore the use of LaTeX for presenting chemical equations and calculations.
  • Investigate common pitfalls in calculating pH for polyprotic acids.
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Chemistry students, educators, and professionals involved in acid-base chemistry, particularly those focusing on polyprotic acids and equilibrium calculations.

FredericChopin
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Homework Statement


Find the pH of 0.02025 M tartaric acid using the method of multiple equilibria given that its Ka1 value is 9.2*10-4 and its Ka2 value is 4.31*10-5.


Homework Equations


Kaoverall = Ka1 * Ka2


The Attempt at a Solution


Please check the Word document.

Is my method and calculation correct?

Thank you.
 

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For some reason I can't open the file. .docx is not the best format. Try to post it here using LaTeX, or - at worst - as an image.
 
Hm... that's strange.

I'll upload images files then (LaTeX is too much trouble...)

They're in order of page number.
 

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Seems like you have completely ignored presence of HT-.

pH of the 0.02025 M tartaric acid is 2.41, as long as your calculations don't reproduce this result they are wrong.
 

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The reason I'm asking is because I answered the same question but instead used the step-by-step equilibrium method and I got a different answer.

I can't see where I went wrong though. Both methods should yield the same answer.

They're in order of page number.
 

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Borek said:
Seems like you have completely ignored presence of HT-.

pH of the 0.02025 M tartaric acid is 2.41, as long as your calculations don't reproduce this result they are wrong.

Hm... but wouldn't it cancel out in the equation?
 
No. Just because it cancels out in a partial system of equations doesn't mean it shouldn't be taken into account. Overall equation doesn't say a word about intermediate steps, which doesn't mean they don't exist.

Correct derivation is shown on the page I already linked to.
 
Ah. You're right. I see where I went wrong.

It's not working because I'm writing an overall reaction that doesn't exist. And it wouldn't work unless there's a third reaction. Otherwise, as you said, I would miss the intermediate reactions.

Thank you.
 

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