pH of a solution from 200 mL acetic acid mixed with 100 mL NaOH

[Rron]

Homework Statement

A solution is prepared by mixing 200 mL of 0.2 M CH3COOH with 100 mL of 0.1 M of NaOH solution.Calculate the pH of the solution.(Ka=1.8x10^-5)


I really don't know how to start this, so please help me.Its going to be a similar one on my exam tomorrow.

Thanks.

 

[symbolipoint]

Some of what you are missing is to fill in THIS information more precisely:

Homework Equations

and rules[/B]

CH₃OOH + NaOH ⇔ NaCH₃OO + H₂O

Ka = $\frac{[H][CH3OO]}{[CH3OOH]}$

 

[Borek]

Buffer and Henderson-Hasselbalch equation.