I Phonon emission : Discrete event or a process with inner detail?

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Phonon emission is typically viewed as a discrete event, similar to photon emission, but the nature of this discreteness is debated. While photon emission is often considered an atomic event without further breakdown, phonon emission may involve more complex underlying processes. The discussion raises questions about the implications of emitting fractional photons and how to measure differences between discrete and continuous emission processes. Unlike photons, phonons are understood to emerge from more fundamental theories, suggesting that phonon interactions may be more intricate. Ultimately, the conversation highlights the need for further exploration into the fundamental nature of both phonons and photons.
Swamp Thing
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If I understand correctly, when an electron drops to a lower energy state and emits a phoTon, this is a discrete or "atomic" event in the sense that it can't be meaningfully broken down in terms of more detailed sub-processes or interactions.

Now in the case of phoNon emission, it is also usually thought of as a discrete event... but is this done merely for convenience and simplicity, or is it also inherently discrete/"atomic" with no inner machinery?
 
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What would it mean to emit half a photon? More generally, what kind of measurement could you make to distinguish those two possibilities?
 
We know that phonon interactions emerge from a more fundamental theory in which phonons are not fundamental objects. We do not have such a knowledge for photons, even though we have some theoretical candidates (e.g. string theory). So I would reverse the question. The emission of phonons can be "meaningfully broken down in terms of more detailed sub-processes or interactions", while the open question is whether it can be done for photons.
 
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For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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