Phosphate Buffer Concentration Calculation

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SUMMARY

The discussion focuses on calculating the concentrations of Na2HPO4 and NaH2PO4 needed to prepare a 1M phosphate buffer at pH 7.8, using the Henderson-Hasselbalch equation. The user correctly sets up the equation with pH = pKa + log(base/conjugate acid) and derives the ratio of base to acid as 3.89. The final concentrations are calculated as 0.2045M for Na2HPO4 and 0.7955M for NaH2PO4. The approach is validated by other users, confirming the calculations are accurate.

PREREQUISITES
  • Understanding of the Henderson-Hasselbalch equation
  • Knowledge of buffer solutions and their components
  • Basic algebra for solving equations
  • Familiarity with molarity and concentration calculations
NEXT STEPS
  • Study the Henderson-Hasselbalch equation in detail
  • Learn about buffer preparation techniques in laboratory settings
  • Explore the use of buffer calculators for various pH levels
  • Investigate stoichiometry in relation to acid-base reactions
USEFUL FOR

Chemistry students, laboratory technicians, and anyone involved in buffer preparation and pH management in biochemical applications.

hianghao
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Homework Statement


To prepare 1M phosphate buffer pH7.8. pKa=7.21. How much molar of Na2HPO4 and NaH2PO4 to be added
I have no confidence in my answer... Can anyone pls have a check?

Homework Equations


pH=pKa+lg (base/conjugate acid)

The Attempt at a Solution


7.8=7.21 +lg (a/b)
0.59=lg (a/b)
a/b=3.89
a+b=1-----1
a=1-b -----2
(1-b)/b=3.89
b=0.2045 -Na2HPO4
a=0.7955 -NaH2PO4

Is my way of doing it correct? Did i forget to calculate other things that i must?
 
Last edited:
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Your approach is correct. But:

hianghao said:
a/b=3.89
a+b=1-----1

OK

(1-b)/b=1

Check your math.

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