Photoelectic cross-section question

  • Thread starter Thread starter jsc314159
  • Start date Start date
  • Tags Tags
    Cross-section
Click For Summary
SUMMARY

The discussion centers on the photoemission cross-section from the 1s state of a charge Z atom, establishing that the cross-section, denoted as σ, is proportional to Z^5 in the limit where p_fa_0/Zħ >> 1. The equation for σ is provided as σ = (128a_0^3πe^2p_f^3)/(3mħ^3ω_c[1+p_f^2a_0^2/ħ^2]^4). A key point raised is the transformation of the Bohr radius a_0 to a_0/Z, which is attributed to the change in the Coulomb potential in the Hamiltonian from q^2/r to Zq^2/r.

PREREQUISITES
  • Understanding of photoemission and its relation to atomic states
  • Familiarity with the Bohr model of the atom, specifically the concept of the Bohr radius
  • Knowledge of quantum mechanics, particularly Hamiltonian mechanics
  • Basic grasp of the Coulomb potential and its implications in atomic physics
NEXT STEPS
  • Study the derivation of the photoemission cross-section in quantum mechanics
  • Explore the implications of the Bohr model on atomic structure and behavior
  • Investigate the role of the Coulomb potential in quantum systems
  • Learn about the physical significance of the parameters in the photoemission equation
USEFUL FOR

Students and researchers in atomic physics, particularly those focusing on photoemission processes and quantum mechanics. This discussion is beneficial for anyone seeking to understand the relationship between atomic charge and photoemission cross-sections.

jsc314159
Messages
18
Reaction score
1

Homework Statement


Show that if we consider photoemission from the 1s state of a charge Z atom,
<br /> \sigma \propto Z^5}} <br />, in the limit p_fa_0/Z\hbar &gt;&gt; 1.<br />

Homework Equations



<br /> \sigma = \frac{128a_0^3\pi e^2p_f^3}{3m\hbar^3\omegac[1+p_f^2a_0^2/\hbar^2]^4}} <br />

The Attempt at a Solution


Actually I know how to do this. a_0 -&gt; a_0/Z. My question is why is this so? What is the physical interpretation/what does it mean?

jsc
 
Physics news on Phys.org
I think the reason a_0 -&gt; a_0/Z is because the Coulomb potential in the Hamiltonian changes from q^2/r to Zq^2/r. Is that right?

jsc
 

Similar threads

Replies
15
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
4
Views
2K
Replies
1
Views
816
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
11
Views
2K
Replies
8
Views
3K