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Photoelectic cross-section question

  • Thread starter jsc314159
  • Start date
  • #1
21
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Homework Statement


Show that if we consider photoemission from the 1s state of a charge Z atom,
[tex]
\sigma \propto Z^5}}
[/tex], in the limit [tex] p_fa_0/Z\hbar >> 1.
[/tex]


Homework Equations



[tex]
\sigma = \frac{128a_0^3\pi e^2p_f^3}{3m\hbar^3\omegac[1+p_f^2a_0^2/\hbar^2]^4}}
[/tex]



The Attempt at a Solution


Actually I know how to do this. [tex] a_0 -> a_0/Z [/tex]. My question is why is this so? What is the physical interpretation/what does it mean?

jsc
 

Answers and Replies

  • #2
21
0
I think the reason [tex] a_0 -> a_0/Z [/tex] is because the Coulomb potential in the Hamiltonian changes from [tex] q^2/r [/tex] to [tex] Zq^2/r [/tex]. Is that right?

jsc
 

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