Photoelectric effect minimum frequency

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Delta2
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Main Question or Discussion Point

Assume fmin is the minimum frequency of photon required for the electron to be ejected.
Why cant we have an electron absorbing 2 photons of frequency fmin/2 thus the total energy will be 2h*(fmin/2)=h*fmin thus the electron to be ejected?
 

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  • #2
clem
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The probability of absorbing two photons is down by a factor of at least 100.
 
  • #3
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The probability of absorbing two photons is down by a factor of at least 100.
So it still can, but it is just unlikely?

What happens when you have many energy levels for the electron to go, so that when the photon hits it it can exist at a higher energy level, and then is hit by another photon before it becomes de-excited?

In The case of no higher energy levels then the electron has no where to go after being hit by first photon and will dissipate the energy before being hit by the second.
 

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