Photons fired from the back of a moving spacecraft

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SUMMARY

The discussion centers on calculating the time it takes for a photon fired from the back of a spaceship, traveling at 3/5c, to reach the front of the spaceship, which is 1 light second long. In the spaceship's reference frame, the photon takes 5/4 seconds to reach the front. However, for a stationary observer, the time measured is 5/2 seconds due to the effects of length contraction and the constancy of the speed of light. The proper length of the spaceship must be specified to accurately determine the time in different reference frames.

PREREQUISITES
  • Understanding of special relativity concepts, including time dilation and length contraction.
  • Familiarity with the equation T=t/(1-v^2/c^2)^1/2 for time transformation.
  • Knowledge of the speed of light (c) and its invariance across reference frames.
  • Basic principles of Newtonian mechanics for comparative analysis.
NEXT STEPS
  • Study the implications of length contraction in special relativity.
  • Learn about the Lorentz transformation equations for time and space.
  • Explore practical applications of time dilation in high-speed travel scenarios.
  • Investigate the relationship between proper length and observed length in different frames of reference.
USEFUL FOR

Students of physics, particularly those focusing on special relativity, educators teaching advanced mechanics, and anyone interested in the implications of relativistic effects on time and space measurements.

Morgan8i6
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Homework Statement



If a passenger at the back of a spaceship traveling at 3/5c fires a photon forward how long will it take to hit the front of the spaceship in the reference frame of the spaceship if it is 1 light second long? How long will it take in the stationary frame?

Homework Equations



T=t/(1-v^2/c^2)^1/2


The Attempt at a Solution


I completed the first half of the problem. Plugging in 1 second in for t (time it takes a photon to travel one light second) and 3/5c (the velocity of the reference frame) for v gives me 5/4 seconds. I just can't figure out what I should be inputting for the variables in the statuary reference frame. The answer sheet says a stationary observer would measure the time T to be 5/2 seconds.
 
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I completed the first half of the problem. Plugging in 1 second in for t (time it takes a photon to travel one light second) and 3/5c (the velocity of the reference frame) for v gives me 5/4 seconds.
No, that is not correct. In the reference frame of the spaceship, the spaceship is at rest. The 3/5c relative to some arbitrary observer somewhere else are completely irrelevant.

I just can't figure out what I should be inputting for the variables in the statuary reference frame.
You can use Newtonian mechanics here, if you like, if you calculate the length of the spaceship - as seen by the observer - with relativistic mechanics first.
 
Morgan8i6 said:
If a passenger at the back of a spaceship traveling at 3/5c fires a photon forward how long will it take to hit the front of the spaceship in the reference frame of the spaceship if it is 1 light second long? How long will it take in the stationary frame?


You should specify in which reference the ship is 1 light second long.

In the most natural case (1 second long is the proper length), then consider that ANY observer will see light with speed ##c##.

Also consider using for the second part of the problem, the length contraction instead of the time dilatation. Meaning, compute in the lab frame which would be the length perceived of the ship, and then use light speed ##c##.
 

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