I Physical interpretation of this coherent state

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The discussion focuses on the coherent state defined as |α⟩ = e^(αA† - α̅A)|0⟩ for a quantum harmonic oscillator, demonstrating that |α⟩ is an eigenvector of the lowering operator A with eigenvalue α. The inner product of two coherent states is calculated, showing that |⟨α|β⟩|² = e^{|\alpha - β|²}, indicating that the set of coherent states spans the space. The mean value of momentum ⟨α|P|α⟩ is found to be proportional to the imaginary part of α, raising questions about its physical interpretation. The discussion suggests that the position and momentum wavefunctions of coherent states evolve similarly to classical systems, supported by Ehrenfest's theorem, which states that their expectation values follow classical equations of motion. Coherent states exhibit minimal uncertainty, making them the closest quantum analogs to classical behavior, especially for large values of |α|.
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Given the usual raising & lowering operators ##A^{\dagger}## & ##A## for a quantum harmonic oscillator, consider a coherent state ##|\alpha\rangle \equiv e^{\alpha A^{\dagger} - \bar{\alpha} A} |0\rangle##. I first check that ##|\alpha\rangle## is an eigenvector of ##A##. I already proved that if ##X##, ##Y## commute with ##[X,Y]## then ## e^{X+Y} = e^{X} e^{Y} e^{-\frac{1}{2}[X,Y]}##, which is applicable here because both ##A^{\dagger}## & ##A## clearly commute with ##[A^{\dagger}, A] = 1##, therefore\begin{align*}
|\alpha \rangle &= e^{\alpha A^{\dagger}} e^{-\bar{\alpha} A} e^{-\frac{1}{2}[\alpha A^{\dagger},-\bar{\alpha} A]} |0\rangle = e^{\frac{1}{2}|\alpha|^2} e^{\alpha A^{\dagger}} |0\rangle
\end{align*}where I used that ##e^{-\bar{\alpha} A}|0 \rangle = (1 - \bar{\alpha} A + \dots)|0\rangle = |0 \rangle##. Upon application of ##A##,\begin{align*}
A|\alpha\rangle = e^{\frac{1}{2}|\alpha|^2} (A e^{\alpha A^{\dagger}}) |0 \rangle = e^{\frac{1}{2}|\alpha|^2} ([A , e^{\alpha A^{\dagger}}] + e^{\alpha A^{\dagger}} A) |0 \rangle &= e^{\frac{1}{2}|\alpha|^2} (\alpha e^{\alpha A^{\dagger}} + e^{\alpha A^{\dagger}} A) |0 \rangle \\
&= \alpha e^{\frac{1}{2}|\alpha|^2} e^{\alpha A^{\dagger}} |0\rangle \\
&= \alpha |\alpha \rangle
\end{align*}which means that ##|\alpha \rangle## is of eigenvalue ##\alpha##. I make use of a similar operator identity ##e^X e^Y = e^Y e^X e^{[X,Y]}## to calculate the inner product of two general states:\begin{align*}
\langle \alpha | \beta \rangle = e^{\frac{1}{2} (|\alpha|^2 + |\beta|^2)}\langle 0 | e^{\bar{\beta} A} e^{\alpha A^{\dagger}}| 0 \rangle &= e^{\frac{1}{2} (|\alpha|^2 + |\beta|^2)}\langle 0 | e^{\alpha A^{\dagger}} e^{\bar{\beta} A} e^{[\bar{\beta} A, \alpha A^{\dagger}]} | 0 \rangle \\
&= e^{\frac{1}{2}(|\alpha|^2 + |\beta|^2)}e^{-2\alpha \bar{\beta}} \langle 0 | e^{\alpha A^{\dagger}} e^{\bar{\beta} A} | 0 \rangle \\
&= e^{\frac{1}{2}(|\alpha|^2 -2\alpha \bar{\beta} + |\beta|^2))}
\end{align*}where I used the fact that ##\langle 0 | e^{\alpha A^{\dagger}} \leftrightarrow e^{\bar{\alpha} A} |0\rangle##. It is therefore also the case that ##|\langle \alpha | \beta \rangle|^2 = e^{|\alpha - \beta|^2}##, that the set ##\{ |\alpha \rangle \}_{\alpha \in \mathbf{C}}## spans the space and that one can select a basis from a suitable subset of ##\{ |\alpha \rangle \}_{\alpha \in \mathbf{C}}##.

To consider the physical interpretation of ##|\alpha(t) \rangle## for a general complex ##\alpha \in \mathbf{C}##, it is advised to calculate ##\langle \alpha | P | \alpha \rangle##,\begin{align*}
\langle \alpha | P | \alpha \rangle = \frac{i}{\sqrt{2}} \langle \alpha | (A^{\dagger} - A) | \alpha \rangle &= \frac{i}{\sqrt{2}} \langle \alpha | (\bar{\alpha} - \alpha) |\alpha \rangle \\
&= \frac{i}{\sqrt{2}} (\bar{\alpha} - \alpha) \\
&= \sqrt{2} \mathrm{Im}(\alpha)
\end{align*}How am I supposed to interpret that the mean value of the momentum is proportional to the imaginary part of ##\alpha##? Also, how would I use this result to describe, qualitatively, how the position and momentum space wavefunctions evolve (I already worked out that ##|\alpha(t) \rangle = e^{-i\omega t/2} | e^{-i\omega t} \alpha \rangle##?
 
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Thanks for the link. Is there a way to see that the position and momentum basis wavefunctions oscillate like in a classical system without further calculation apart from the OP? I only ask because my problem sheet suggests that it is not necessary to work anything else out explicitly.
 
You can refer to Ehrenfest's theorem. Since the harmonic oscillator has a linear set of equations of motion for ##x## and ##p## the expectation values fulfill precisely the same equations of motion as the classical harmonic oscillator. A coherent state is one of minimal uncertainty product, ##\Delta x \Delta p=\hbar/2##, and thus are closest to a classical description of the system, especially for large ##|\alpha|##.
 
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We often see discussions about what QM and QFT mean, but hardly anything on just how fundamental they are to much of physics. To rectify that, see the following; https://www.cambridge.org/engage/api-gateway/coe/assets/orp/resource/item/66a6a6005101a2ffa86cdd48/original/a-derivation-of-maxwell-s-equations-from-first-principles.pdf 'Somewhat magically, if one then applies local gauge invariance to the Dirac Lagrangian, a field appears, and from this field it is possible to derive Maxwell’s...

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