MHB Physics: AM Radio Station Emits Photons/sec at 1000-kHz

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An 84-kW AM radio station broadcasting at 1000 kHz emits photons at a specific rate determined by the energy of each photon. The energy of a single photon at this frequency is calculated using Planck's constant, resulting in approximately 6.626 x 10^-28 Joules. Given the station's power output of 84,000 Joules per second, the number of photons emitted each second can be determined using the formula N = Es / Eν. This calculation reveals the significant number of photons transmitted by the antenna. The discussion effectively illustrates the relationship between radio frequency, photon energy, and emission rates.
yakin
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Physics: An 84-kW AM radio station broadcasts at 1000-kHz. How many photons are emitted each second by the transmitting antenna? (h=6.626E-32 Js)
 
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yakin said:
Physics: An 84-kW AM radio station broadcasts at 1000-kHz. How many photons are emitted each second by the transmitting antenna? (h=6.626E-32 Js)

Energy of a single photon with frequency $$\nu$$ is:

$$E_{\nu}=h \nu$$

where $$h$$ Plank's constant.

So for our 1000 kHz signal the energy of a single photon is:

$$E_{\nu}=h \nu= 6.626\times 10^{-32} \times 1000 \times 1000= 6.626\times 10^{-28}$$ J

The radio station is emitting $$E_s=8.4\times 10^4$$ Joules per second, so the number of photons emited per second is:

$$N=\frac{E_s}{E_{\nu}}$$

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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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