MHB Physics: AM Radio Station Emits Photons/sec at 1000-kHz

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An 84-kW AM radio station broadcasting at 1000 kHz emits photons at a specific rate determined by the energy of each photon. The energy of a single photon at this frequency is calculated using Planck's constant, resulting in approximately 6.626 x 10^-28 Joules. Given the station's power output of 84,000 Joules per second, the number of photons emitted each second can be determined using the formula N = Es / Eν. This calculation reveals the significant number of photons transmitted by the antenna. The discussion effectively illustrates the relationship between radio frequency, photon energy, and emission rates.
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Physics: An 84-kW AM radio station broadcasts at 1000-kHz. How many photons are emitted each second by the transmitting antenna? (h=6.626E-32 Js)
 
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yakin said:
Physics: An 84-kW AM radio station broadcasts at 1000-kHz. How many photons are emitted each second by the transmitting antenna? (h=6.626E-32 Js)

Energy of a single photon with frequency $$\nu$$ is:

$$E_{\nu}=h \nu$$

where $$h$$ Plank's constant.

So for our 1000 kHz signal the energy of a single photon is:

$$E_{\nu}=h \nu= 6.626\times 10^{-32} \times 1000 \times 1000= 6.626\times 10^{-28}$$ J

The radio station is emitting $$E_s=8.4\times 10^4$$ Joules per second, so the number of photons emited per second is:

$$N=\frac{E_s}{E_{\nu}}$$

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