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Physics: An 84-kW AM radio station broadcasts at 1000-kHz. How many photons are emitted each second by the transmitting antenna? (h=6.626E-32 Js)
An 84-kW AM radio station broadcasting at 1000 kHz emits photons at a rate determined by the energy of each photon and the total energy output. Using Planck's constant (h = 6.626E-34 Js), the energy of a single photon is calculated as Eν = hν = 6.626 × 10^-34 × 1,000,000 Hz = 6.626 × 10^-28 J. The total energy emitted per second is 8.4 × 10^4 Joules, leading to the calculation of the number of photons emitted per second as N = Es / Eν.
PREREQUISITESPhysicists, electrical engineers, and students studying radio frequency transmission and photon behavior in electromagnetic waves.
yakin said:Physics: An 84-kW AM radio station broadcasts at 1000-kHz. How many photons are emitted each second by the transmitting antenna? (h=6.626E-32 Js)