Physics centripetal acceleration/ mass

Click For Summary
SUMMARY

The discussion focuses on calculating the mass of a planet based on the orbital characteristics of its moon, which has a period of 1.8 days and an orbital radius of 420,000,000 meters. The moon's orbital speed was calculated to be 16,968.5 m/s, and the centripetal acceleration was determined to be 0.69 m/s². A key insight provided was to equate centripetal force with gravitational force, leading to the formula Fc = Fg. The final mass of the planet was estimated to be on the order of 10^27 kg, similar to Jupiter's mass.

PREREQUISITES
  • Understanding of centripetal acceleration and gravitational force
  • Familiarity with orbital mechanics and Kepler's laws
  • Knowledge of the gravitational constant (G = 6.67E-11 N(m/kg)²)
  • Ability to manipulate equations involving velocity, radius, and period
NEXT STEPS
  • Study the derivation of the centripetal force equation, Fc = mv²/R
  • Learn how to apply Kepler's Third Law to determine planetary masses
  • Explore the relationship between orbital period and radius in circular motion
  • Investigate the gravitational constant and its applications in astrophysics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and orbital dynamics, as well as educators looking for practical examples of gravitational calculations.

astru025
Messages
163
Reaction score
0

Homework Statement



A moon orbits a planet of unknown mass with a period of 1.8 days. If the radius of the moon's orbit is 420,000,000 meters, find the mass of the planet.

Homework Equations



For the speed of the moon I got: v=2 x pie x r / v
2 x pie x 420000000 / v = 1.8 days or 155520 seconds since speed is m/s.
v= 16968.5 m/s.

For the centripetal acceleration of the moon I got this: a= v^2/ r
16968.5 ^2 / 420000000 = .69 s

Now for the mass of the planet I am not quite sure how to figure out. If I know the speed and centripetal acceleration for the moon how do I use this to get the mass of the planet orbiting the moon??

The Attempt at a Solution


My attempt but was un successful:
v^2= G (Me/r)
16968.5 m/s^2= 6.67E-11 ( Me/420000000)
1.03E10
 
Physics news on Phys.org
Looks pretty good! The first bit confuses me because you use v for velocity and also for period (usually T), but I agree with your velocity number. I also agree with the a = .69, but the units are m/s², not seconds. I don't quite see how you are getting the mass in the last part. It appears you forgot to square the velocity.

Astru, I would like to offer you a hot tip. Whenever you see the word "orbit" in a problem, immediately write down "centripetal force equals gravitational force" or Fc = Fg. Then replace the Fg with your big G formula and Fc with either the formula with v in it or the one with T in it. In this case, you are given the period, so use the one with the T and don't bother to calculate the velocity. (If you only have Fc = mv²/R, then replace the v with 2πR/T to get Fc = 4π²mR/T²)
You'll soon have an equation where you can cancel the mass of the moon and solve for the mass of the planet in terms of period and radius - only one calc instead of three so less chance for error! For me, the mass works out to roughly 10 to the 15th kg.
 
You forgot to square the speed, haven't you?

The parameters are pretty close to those of Jupiter's satellite Io. So I expect you'll get a mass close to Jupiter's mass. Order of magnitude 10^27 kg.
 
Last edited:

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
Replies
1
Views
2K
Replies
12
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 28 ·
Replies
28
Views
3K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K