Physics help please determining distance of box pushed

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SUMMARY

The discussion centers on calculating the distance a 20 kg box is pushed by an 8 N force, resulting in a final speed of 2 m/s. The correct approach involves using the kinematic equation Vf² - Vo² = 2*a*displacement, where Vf is the final velocity, Vo is the initial velocity (0 m/s), and a is the acceleration derived from the net force using Fnet = ma. The user initially calculated the distance as 10 m incorrectly, highlighting the importance of correctly applying kinematic equations in physics problems.

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  • Understanding Newton's Second Law (Fnet = ma)
  • Familiarity with kinematic equations
  • Basic knowledge of acceleration calculation
  • Concept of displacement in physics
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  • Learn how to calculate acceleration from net force using Fnet = ma
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lbella026
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Homework Statement


A block has a mass of 20kg is at rest on the floor. This block is then pushed by a horizontal force of 8N across the floor. The final speed is 2 m/s. Determine the distance the box was pushed.


Homework Equations


Fnet=ma
d=(t)(s)
a=(chand in velocity)/(change in time)


The Attempt at a Solution


Using all three equations I found the distance to be 10m. But this answer is incorrect. I can't figure out what I am doing wrong.
 
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lbella026 said:

Homework Statement


A block has a mass of 20kg is at rest on the floor. This block is then pushed by a horizontal force of 8N across the floor. The final speed is 2 m/s. Determine the distance the box was pushed.


Homework Equations


Fnet=ma
d=(t)(s)
a=(chand in velocity)/(change in time)


The Attempt at a Solution


Using all three equations I found the distance to be 10m. But this answer is incorrect. I can't figure out what I am doing wrong.

have you used the kinematic equation Vf^2 - Vo^2 = 2*a*displacement ?

I think you figured out acceleration a, properly...(assume we have a frictionless surface). So if you know a, Vf and Vo, you can figure out displacement (or distance the box moved).
 

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