Physics help- tangential acceleration

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To determine the car's acceleration at t=11s, the relevant equations include Newton's second law (F=ma) and the formula for tangential acceleration (a_t = F/m). Given the car's mass of 1500kg and a constant forward force of 1300N, the tangential acceleration can be calculated as a_t = 1300N / 1500kg, resulting in approximately 0.87 m/s². Additionally, since the car is moving in a circular path, centripetal acceleration must also be considered, calculated using a_c = v²/r, where r is the radius of the track. The discussion emphasizes the importance of breaking down the problem into components and applying the correct physics principles to find the total acceleration.
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A 1500kg car starts from rest and drives around a flat 50m-diameter circular track. The forward force provided by the car's drive wheels is a constant 1300N. What is the magnitude of the car's acceleration at t=11s?
 
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you should go to the homework section and state your thoughts on the problem, list the equations you think you need, show whatever wrk you have done so far and explain where you are getting stuck.

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