Physics linear momentum/ average force

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To solve for the average force exerted by the floor on the rubber ball, first calculate the linear momentum before the collision, which is 0.6 kg·m/s downward. After the bounce, the ball's momentum is -0.6 kg·m/s upward, indicating a change in momentum of 1.2 kg·m/s. Using the formula for net force, divide this change in momentum by the collision time of 0.05 seconds, resulting in an average force of 24 N directed upward. This analysis highlights the importance of considering momentum direction in calculations.
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Homework Statement



A very hard rubber ball (m = 0.2 kg) is falling vertically at 3 m/s just before it bounces on the floor. The ball rebounds back at essentially the same speed. If the collision with the floor lasts 0.05 s, what is the average force exerted by the floor on the ball?

Homework Equations



Net force= change in momentum/ time taken
Linear momentum= mass x velocity

The Attempt at a Solution


I found the linear momentum of the ball before it hits the ground: .2 kg x 3 m/s= .6
After this I am lost and am not sure what I do next. I not sure what I need to do in order to find average force from this information.
 
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Now you have the initial momentum find the final momentum... Then apply the formula for average force...
 
... Bearing in mind that momentum is a vector, so if you are measuring momentum as positive downwards then after the bounce it will be negative.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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