Physics: Multiplying Unit vectors

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Homework Help Overview

The discussion revolves around the multiplication of unit vectors, specifically focusing on the cross product. The original poster is trying to understand the expression (i^×j^)×k^ and is seeking clarification on the results of such operations.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply known cross product results but is uncertain about the outcome of multiplying k^ by itself. Some participants suggest that additional properties of the cross product, such as bilinearity and anti-commutativity, are relevant to the discussion.

Discussion Status

Participants are exploring the properties of vector multiplication and discussing the implications of the cross product. There is an acknowledgment of the need for a deeper understanding of vector operations, but no consensus has been reached on the specific question posed.

Contextual Notes

There is mention of the ambiguity in terminology regarding "k^ squared," which may refer to different types of vector products. The original poster is also working within the constraints of homework guidelines that may limit the type of assistance they can receive.

RaeMarine
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[Moderator note: Post moved from New Member Introductions forum, so no template]

I am having trouble understanding how to multiply unit vectors. I know that: (please excuse the notation)
i^×j^ = k^
j^×k^ = i^
k^×i^ = j^

The question I am stuck on is: What is (i^×j^)×k^?
So far I have (i^×j^) = k^, which would mean the above equation turns into k^×k^. I am supposed to represent the answer in unit vector form, but the only answers I can come up with are k^ squared or -1... What am I missing? All help is appreciated!
 
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RaeMarine said:
I am having trouble understanding how to multiply unit vectors. I know that: (please excuse the notation)
i^×j^ = k^
j^×k^ = i^
k^×i^ = j^

The question I am stuck on is: What is (i^×j^)×k^?
So far I have (i^×j^) = k^, which would mean the above equation turns into k^×k^. I am supposed to represent the answer in unit vector form, but the only answers I can come up with are k^ squared or -1... What am I missing? All help is appreciated!
Don't ask technical questions in your Introduction post.

You should learn some basic facts about dot products and cross products of unit vectors.

https://en.wikipedia.org/wiki/Cross_product
 
What can I ask in my introduction post?
 
RaeMarine said:
What can I ask in my introduction post?
You shouldn't ask anything. The purpose of an introduction post is to introduce yourself.
 
RaeMarine said:
I am having trouble understanding how to multiply unit vectors. I know that: (please excuse the notation)
i^×j^ = k^
j^×k^ = i^
k^×i^ = j^
If that is all you know then you don't know enough to calculate anything else! You would also need to know that the "cross product" of two vectors is "bilinear" meaning (au^+ bv^) x w^= a(u^xw^)+ b(v^xw^) and that the cross product is "anti-commutative" meaning that u^xv^= -v^xu^

The question I am stuck on is: What is (i^×j^)×k^?
So far I have (i^×j^) = k^, which would mean the above equation turns into k^×k^. I am supposed to represent the answer in unit vector form, but the only answers I can come up with are k^ squared or -1... What am I missing? All help is appreciated!
There are three different kinds of "multiplication" defined for vectors, the "scalar product", of a scalar with a vector, returning a vector, the "dot product" (also called "inner product"), of two vectors, returning a scalar, and the "cross product", that you are talking about here, of two vectors, returning a vector. The terminology "k^ squared" is ambiguous because that would be a product of two vectors which could be either the dot product or the cross product. To find the cross product of k with itself, use the fact that "u^xv^= -v^xu^" with both u^ and v^ equal to k^ that gives k^xk^= -k^xk^. What does that tell you?
 

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