Physics problem kindly explain how to arrive the answer.

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Homework Help Overview

The problem involves two trains starting from different stations and accelerating towards each other. The subject area includes kinematics and motion equations, focusing on uniform acceleration and relative motion.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss writing equations for the positions of the trains over time and question the correctness of their calculations. There is an emphasis on the need to establish clear equations for each train's motion.

Discussion Status

The discussion is ongoing, with participants attempting to derive equations for the trains' positions. Some guidance has been offered regarding the structure of the equations, but there is no consensus on the correctness of the initial attempts or the assumptions made regarding the trains' motions.

Contextual Notes

Participants express confusion about specific values used in the equations and the treatment of the trains' motion after reaching their cruising speeds. There is also uncertainty regarding the setup of the problem, particularly in defining the origin and direction of motion.

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Homework Statement


Two trains start at the same time from stations A and B (6km apart ) respectively in opposite tracks. train A accelerates uniformly at the rate of 0.5 meter per second square until it reaches a speed of 54 kmph, while train B accelerates uniformly at the rate of 0.6 meter per second square until it reaches a speed of 72 kmph and then travels at this speed. Determine when and where both will cross each other


Homework Equations


i don't know what equation to use...


The Attempt at a Solution


i tried equating there distance but it will just complicate the equation...
please help...i would like to know how to get the answer..
 
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hi herbgriffin! :wink:

start by writing out the two equations for the positions of the two trains at any time t (put the origin, x = 0, at A) …

what do you get? :smile:
 
i will get train a will be 225 m at t=30s while train b is 333.33 m at t=33.33s. I don't know if this is right...
 
no, write two equations

always write equations!
 
x=15+[(1/2) (0.5)t^2] train A
x= 20+[(1/2) (0.6) t^2] train B
please correct me if i am wrong i am really confused
 
hi herbgriffin! :smile:

(try using the X2 icon just above the Reply box :wink:)
herbgriffin said:
x=15+[(1/2) (0.5)t^2] train A
x= 20+[(1/2) (0.6) t^2] train B
please correct me if i am wrong i am really confused

your 1/2 (0.5)t2 and 1/2 (0.6)t2 parts are correct,

but i don't understand where your 15 and 20 come from :confused:

also you haven't shown them traveling in opposite directions,

and you haven't dealt with the steady motion after each trains reaches its cruising speed
 

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