Physics Question Over 2 Dimensional Friction Problems

[Xazerd]

The glass is blissfully unaware of the tension in the string and of gravity acting on the bucket. Which forces act directly on the glass, and by doing so provide the centripetal force ( so don't answer "centripetal force").

Normal Force?

 

[haruspex]

Thank You, but I already solved that one now ( I got Net Force= Normal Force- Weight + (Mass*Velocity^2)/radius.)

That equation is not correct, in a couple of ways. Perhaps you've typed it out wrongly?

 

[haruspex]

T + mg = (mv^2)/r

Think again. At what point in the loop is the tension greatest?

 

[pgardn]

Think again. At what point in the loop is the tension greatest?

Aha again!

I was using the FBD for part a)

The problem said Maximum tension. This would happen at the bottom of the loop.

So T - mg = (mv^2)/r

It always helps to answer the questions that are actually asked.
Sorry to the OP. Thanks to Mr. H!

 

[Xazerd]

Aha again!

I was using the FBD for part a)

The problem said Maximum tension. This would happen at the bottom of the loop.

So T - mg = (mv^2)/r

It always helps to answer the questions that are actually asked.
Sorry to the OP. Thanks to Mr. H!

So is this the equation I use for part c and d, but I have to combine the mass of both the bucket and glass?

 

[pgardn]

So is this the equation I use for part c and d, but I have to combine the mass of both the bucket and glass?

Not for part c)

You got part c.

Gravity the sole actor for the centripetal force in c, so mass cancels.

Part d) would occur at the bottom of the circular path. So the tension, or more directly the normal force would act up, and gravity acts down. If you combine mass of the glass and the bucket then you can use tension.

 

[Xazerd]

Not for part c)

You got part c.

Gravity the sole actor for the centripetal force in c, so mass cancels.

Part d) would occur at the bottom of the circular path. So the tension, or more directly the normal force would act up, and gravity acts down. If you combine mass of the glass and the bucket then you can use tension.

Ok. Got it. Thanks!

 

[pgardn]

Ok. Got it. Thanks!

Sorry I did not read the question more carefully and used part a) for everything.

 

[Xazerd]

No Problem!