Physics; two forces on an object

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Two forces, FA and FB, are acting on a 16.0 kg object, resulting in different accelerations based on their directions. When both forces act eastward, the acceleration is 0.900 m/s², leading to a net force calculation of 14.4 N. In the scenario where FA is east and FB is west, the acceleration decreases to 0.400 m/s², allowing for a second equation based on the net force. The discussion emphasizes using simultaneous equations to solve for the magnitudes of FA and FB. The solution involves combining the two equations derived from the different scenarios to find the individual force values.
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Homework Statement



Two forces FA and FB are applied to an object whose mass is 16.0 kg. The larger force is FA. When both forces point due east, the object's acceleration has a magnitude of 0.900 m/s2. However, when FA points due east and FB points due west, the acceleration is 0.400 m/s2, due east. Find the magnitude of FA and the magnitude of FB.

Homework Equations





The Attempt at a Solution



well Fnet= Fa+Fb= ma
so Fnet = 16*0.9
Fnet= 14.4
now what do i do?
 
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When both are in the same direction

Fa+Fb=ma (a = 0.9)

when in opposite directions Fa-Fb=ma, this a is in the second line of the problem
 
yes so Fa+Fb=14.4 how do i find the value of each one?
 
triplel777 said:
yes so Fa+Fb=14.4 how do i find the value of each one?

you have


Fa+Fb= constant

and

Fa-Fb= other constant


two equations with two unknowns, solve simultaneously.
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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