Picard-Vessiot Extension over a Differential Field?

Click For Summary

Discussion Overview

The discussion revolves around the existence of a Picard-Vessiot extension of a differential field F with a linear algebraic group G over the constant field C of F. Participants explore the conditions under which such an extension can be constructed and the implications of these conditions on the Galois theory of Picard-Vessiot extensions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant suggests finding a Picard-Vessiot extension E/F with G(E/F)=GL_n(C) as a starting point, questioning whether such an extension exists.
  • Another participant proposes that if G is viewed as a subgroup of GL_n(C)=G(E/F), then the fixed field E^G can be considered, and if the Galois theory behaves analogously to classical Galois theory, then E/E^G should also be a Picard-Vessiot extension with G(E/E^G) equal to G.
  • A later reply confirms that the previous proof holds under the assumption that the field of constants C is algebraically closed, noting that this condition is necessary for the analogue of Artin's theorem to apply to Picard-Vessiot extensions.
  • One participant expresses uncertainty about the implications if C is not algebraically closed.

Areas of Agreement / Disagreement

Participants generally agree on the validity of the proof under the assumption that C is algebraically closed. However, there is uncertainty regarding the situation when C is not algebraically closed, indicating that the discussion remains unresolved in this aspect.

Contextual Notes

The discussion highlights the dependence on the algebraic closure of the field of constants C for the validity of certain claims regarding Picard-Vessiot extensions and their Galois groups.

KarmonEuloid
Messages
3
Reaction score
0
Given a differential field F and a linear algebraic group G over the constant field C of F, find a Picard-Vessiot extension of E of F with G(E/F)=G:

This isn't homework, just something I saw in a book that I was curious about. The author says that this can be shown but doesn't illustrate how. Can anyone help?
 
Physics news on Phys.org
Caveat: I know nothing about this subject. I checked Wikipedia for the relevant definitions, and I believe this works. First find a Picard-Vessiot extension E/F with G(E/F)=GL_n(C) (such a thing does exist, right??). Next, given a linear algebraic group G, view it as sitting in some GL_n(C)=G(E/F), and then consider the fixed field E^G (this notion makes sense, right??). If the Galois theory of Picard-Vessiot extensions works like normal Galois theory (i.e. if you have an analogue of Artin's theorem), then E/E^G should be Picard-Vessiot and G(E/E^G) should be G.

Note that this proof is identical to the standard proof that every finite group G is the Galois group of some extension. (The role of GL_n above is played by S_n here.)
 
morphism said:
Caveat: I know nothing about this subject. I checked Wikipedia for the relevant definitions, and I believe this works. First find a Picard-Vessiot extension E/F with G(E/F)=GL_n(C) (such a thing does exist, right??). Next, given a linear algebraic group G, view it as sitting in some GL_n(C)=G(E/F), and then consider the fixed field E^G (this notion makes sense, right??). If the Galois theory of Picard-Vessiot extensions works like normal Galois theory (i.e. if you have an analogue of Artin's theorem), then E/E^G should be Picard-Vessiot and G(E/E^G) should be G.

Note that this proof is identical to the standard proof that every finite group G is the Galois group of some extension. (The role of GL_n above is played by S_n here.)

This seems to work to me. I reposted it on MathOverflow (giving you credit of course) to see if they could verify it (as that is where the question originally came from), although I would also appreciate it if someone here could check this or provide an alternate answer. Thanks.
 
I read a bit more about this topic and can now confirm that the above proof is correct, provided the field of constants C is algebraically closed. This assumption is apparently necessary for the analogue of Artin's theorem to hold for Picard-Vessiot extensions. See Chapter 6 of Crespo and Hajto, Algebraic Groups and Differential Galois Theory (AMS 2011), freely available here. [Also note: Exercise 7 shows that, for any n, there is a Picard-Vessiot extension E/F with G(E/F)=GL_n(C).]

I don't know what happens if C is not algebraically closed.
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K