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[EQ] \lambda = \frac{hc}{\epsilon} [/EQ]

into the following equation

[EQ] \frac{U}{V} = \int^{\infty}_{0} \frac{8 \pi \epsilon^{3}/(hc)^{3}}{e^{\epsilon / kT}-1} d \epsilon [/EQ]

from which you should get the Planck spectrum as a function of wavelength. So far I've been careful in replacing the differential of epsilon with

[EQ] d \epsilon = - \frac{hc}{\lambda^2} d \lambda [/EQ]

In preparation to plot and solve the integrand, he asks you to express the above equation in terms of hc/kT, which I'm guessing can be done by substituting the value x below.

[EQ] x = \frac{hc}{kT \lambda} [/EQ]

Again being careful to replace the differential of lambda,

[EQ] d \lambda = - \frac{hc}{kT x^2} dx [/EQ]

However as soon as arrange everything in terms of x, it looks exactly like this equation

[EQ] \frac{U}{V} = \frac{8 \pi (kT)^4}{(hc)^3} \int^{\infty}_{0} \frac{x^3}{e^{x}-1} dx [/EQ]

which, according to Schroeder, it shouldn't because when you plot the spectrum in terms of the wavelength the function should NOT peak at 2.82 and look exactly like the spectrum in terms of epsilon. So, what stupid differential mistake am I making?