# Please check this maths question thanx

1. Feb 5, 2007

### faisal

1. The problem statement, all variables and given/known data
(* to the power of) 20m3 equals to
a)2x10-8km3
b)2x10*6cm3
c)2x10*5dm3
d)2x19*9mm3

2. Relevant equations
ok
1000m=1km
so 1km3 is equal to 1000x1000x1000=10*9
so 10*9/20m3=50,000,000

1km3/50x10*6=20
from here i'm confused
..............................
3. The attempt at a solution

iv attempted to use this method for all the above case yet i continue to get confused help would b warmly appreciated

2. Feb 5, 2007

### neutrino

"1km3/50x10*6=20
from here i'm confused"

Does writing it this way make it any easier?
$$\frac{1}{50\times10^{6}} km^3 = \frac{1}{50}\times \frac{1}{10^{6}}km^3 = 20m^3$$

Last edited: Feb 5, 2007
3. Feb 5, 2007

### faisal

sir i'd like to know a step by step approch to tackle this question, can you please provide one thank you

4. Feb 5, 2007

### neutrino

What you've done above is correct (other than leaving out the m^3 at the end), i.e.

What's 1/50? And how would you write 1/106 as a power of 10?