Please check this maths question thanx

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AI Thread Summary
The discussion revolves around solving a math problem involving unit conversions from cubic meters to other volume units. The user is attempting to convert 20m³ into various units, including kilometers, centimeters, decimeters, and millimeters. They express confusion over the calculations, particularly when dividing cubic kilometers by a factor of 50 million. Clarifications are provided regarding the conversion factors and the correct representation of the units, emphasizing the need to express fractions as powers of ten. The conversation highlights the importance of understanding unit conversions and the correct application of mathematical principles in solving such problems.
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Homework Statement


(* to the power of) 20m3 equals to
a)2x10-8km3
b)2x10*6cm3
c)2x10*5dm3
d)2x19*9mm3

Homework Equations


ok
1000m=1km
so 1km3 is equal to 1000x1000x1000=10*9
so 10*9/20m3=50,000,000

1km3/50x10*6=20
from here I'm confused
........

The Attempt at a Solution



iv attempted to use this method for all the above case yet i continue to get confused help would b warmly appreciated
 
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"1km3/50x10*6=20
from here I'm confused"

Does writing it this way make it any easier?
\frac{1}{50\times10^{6}} km^3 = <br /> \frac{1}{50}\times <br /> \frac{1}{10^{6}}km^3 = 20m^3
 
Last edited:
sir i'd like to know a step by step approch to tackle this question, can you please provide one thank you
 
What you've done above is correct (other than leaving out the m^3 at the end), i.e.

1000m=1km
so 1km3 is equal to 1000x1000x1000=10*9
so 10*9/20m3=50,000,000

1km3/50x10*6=20

What's 1/50? And how would you write 1/106 as a power of 10?
 
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Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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