imconfused
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Calculate the % hydrolysis for 1 M Na2CO3 if [OH-] = 5.4x10^-(4)
The discussion focuses on calculating the percentage hydrolysis of a 1 M sodium carbonate (Na2CO3) solution given an hydroxide ion concentration of [OH-] = 5.4x10^(-4). The relevant hydrolysis reactions include the dissociation of carbonate ions (CO3^(2-)) into bicarbonate ions (HCO3^(-1)) and hydroxide ions. The equilibrium constants for the reactions involving carbonic acid (H2CO3) are provided, specifically Ka1 = 4.3x10^(-7) and Ka2 = 5.6x10^(-11). The calculation of Kb values for bicarbonate and carbonic acid is also discussed, leading to the determination of the theoretical percentage hydrolysis.
PREREQUISITESChemistry students, educators, and professionals involved in analytical chemistry or chemical education who are looking to deepen their understanding of hydrolysis and equilibrium in aqueous solutions.
Borek said:Done.
Ignoring template and not showing any effort will lead you nowhere.
imconfused said:CO3^(2-) + H2O -> HCO3^(-1) + OH^(-1)