Determining Rate Constant for Hydrolysis of Ethyl Lactate with Acid Catalysis?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
2 replies · 2K views
sarahrpol
Messages
1
Reaction score
0

Homework Statement


Hydrolysis of ethyl lactate

Determine the value of the rate constant for the hydrolysis of ethyl lactate from the following data.

Mass of ethyl lactate (grams): 0.5956
Concentration of stock HCl solution (M): 0.01023

Standardization titration volumes (of NaOH):

Run Vi (mL) Vf(mL)
1 0.60 15.58
2 15.58 30.66
3 30.66 45.66

Kinetics data:
Run Reaction time (seconds) Vi(mL) Vf(mL)
0 0
1 308 1.72 4.32
2 742 4.32 8.88
3 1303 8.88 14.84
4 1910 14.84 21.66
5 2550 21.66 29.06

Rate constant = ?

Homework Equations


equations are below

The Attempt at a Solution


the rate equation is -d[OH-]/dt = k[OH-][EtL]

but I'm not sure how to find the concentration of OH and the concentration of Ethyl lactate is 0.01203

and then a = 1/2[OH-]o + [Etl]o
1/a-x - 1/a = kt
 
Physics news on Phys.org
What are the titrations for? What do they determine?

OH- is just a catalyst and its concentration doesn't change during the hydrolysis, so your rate equation can't be right.
 
This is really not set out clearly enough to understand or help with.
What are Vi, Vf? What is measured how?
Is this acid catalysis?