Please help Calculate the % hydrolysis for 1 M Na2CO3 if [OH-] = 5.4x10^-(4).

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Discussion Overview

The discussion revolves around calculating the percentage of hydrolysis for a 1 M solution of Na2CO3 given a hydroxide ion concentration of [OH-] = 5.4x10^(-4). The scope includes theoretical calculations, reaction equations, and concepts related to hydrolysis.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant requests help in calculating the % hydrolysis for Na2CO3 based on the provided [OH-] concentration.
  • Another participant questions the initial request, suggesting that the poster should show more effort in their inquiry.
  • A participant provides reaction equations relevant to the hydrolysis of carbonate ions, including the dissociation of CO3^(2-) and its interactions with water.
  • Equilibrium expressions for Kb values are presented, derived from the dissociation constants (Ka1 and Ka2) of carbonic acid (H2CO3).
  • There is a question regarding how to define the percentage of hydrolysis and whether the equilibrium concentration of HCO3- can be calculated from the known [OH-].

Areas of Agreement / Disagreement

Participants express differing views on the adequacy of the original question and the level of detail required for a proper response. There is no consensus on how to approach the calculation or the definition of hydrolysis percentage.

Contextual Notes

Participants have not resolved the definitions or assumptions related to hydrolysis percentage, and there are unresolved steps in the calculations presented.

Who May Find This Useful

Students or individuals interested in the concepts of hydrolysis, carbonate chemistry, and equilibrium calculations in aqueous solutions.

imconfused
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Calculate the % hydrolysis for 1 M Na2CO3 if [OH-] = 5.4x10^-(4)
 
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Done.

Ignoring template and not showing any effort will lead you nowhere.
 
Borek said:
Done.

Ignoring template and not showing any effort will lead you nowhere.

Huh? But I asked my question. This is the only information I was given.

No effort? But I'm stuck! I'm showing some effort by asking for some help here on ONE problem!
 

Homework Statement



Calculate the % hydrolysis for 1 M Na2CO3 if [OH-] = 5.4x10^-(4).

Not sure what to put for the other fields.
 
Do you know any reaction equations? What is hydrolysis?
 
Last edited by a moderator:
Calculate the theoretical % hydrolysis for 1 M solution of Na2CO3

Homework Statement


Calculate the theoretical % hydrolysis for 1 M solution of Na2CO3


Homework Equations


CO3^(2-) + 2H2O -> H2CO3 + 2OH^(-1)

or

CO3^(2-) + H2O -> HCO3^(-1) + OH^(-1)
HCO3^(-1) + H2O -> H2CO3 + OH^(-1)

Chart values for the Ka1 and Ka2 of H2CO3:
Ka1 = 4.3x10^(-7)
Ka2 = 5.6x10^(-11)

The Attempt at a Solution



Kb1 = {[HCO3^(-1)][OH^(-1)]}/[CO3^(-2)] = Kw/Ka2 = [10^(-14)]/[5.6x10^(-11) = 1.78x10^(-4)

Kb2 = {[H2CO3][OH^(-1)]}/[HCO3^(-1)] = Kw/Ka1 = [10^(-14)]/[4.3x10^(-7)] = 2.32x10^(-8)
 
Moderator's note: merged two threads.
 


imconfused said:
CO3^(2-) + H2O -> HCO3^(-1) + OH^(-1)

You know equilibrium concentration of OH- - can you use it to calculate concentration of HCO3-?

How is hydrolysis percentage defined?
 
Last edited by a moderator:

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