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imconfused
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Calculate the % hydrolysis for 1 M Na2CO3 if [OH-] = 5.4x10^-(4)
Borek said:Done.
Ignoring template and not showing any effort will lead you nowhere.
imconfused said:CO3^(2-) + H2O -> HCO3^(-1) + OH^(-1)
The equation for calculating % hydrolysis is (% hydrolysis) = ([OH-]/[initial concentration]) x 100%.
The initial concentration of Na2CO3 is 1 M.
The concentration of hydroxide ions can be calculated using the formula [OH-] = Kw/[H+] where Kw is the ion product constant for water and [H+] is the concentration of hydrogen ions.
The ion product constant for water (Kw) is 1 x 10^-14 at 25°C.
The % hydrolysis for 1 M Na2CO3 with [OH-] = 5.4x10^-(4) is 0.054%.