Please help - Efficiency of car engine question Unit test tomorrow

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SUMMARY

The discussion centers on calculating the chemical energy required for a car engine with an efficiency of 12% to move a car a distance of 450 meters at a constant speed of 21 m/s, given a force of 18000 N. The key formula used is the efficiency equation: Efficiency(%) = 100 * Energy Out / Energy In. By rearranging this formula, the user derived Energy In = 100 * force * distance / Efficiency, leading to the conclusion that the necessary chemical energy can be calculated directly using the provided values.

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Please help -- Efficiency of car engine question... Unit test tomorrow

Homework Statement


A car's engine is only 12% efficient at converting chemical energy in gasoline into mechanical energy. If it takes 18000 N of force to keep the car moving at a constant speed of 21 m/s, how much chemical energy would be needed to move the car a distance of 450 m at this speed?

Homework Equations


(Eout/Ein)100%
Ek=1/2mv^2
Et=Ek+Eg

The Attempt at a Solution



(Eout/Ein)100%

18000N x 450m/ 18000N x 21 x Ek = 12%
and then I solved for energy
I know this is completely wrong but i just don't understand how to do this question without having the mass... I have my unit test tomorrow and this is the only question I don't understand on the review! PLEASE help me I'm having trouble understanding the efficiency questions, especially this one! I just don't know how else to attempt it!
 
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Have you been taught..

Work (aka Energy) = force * distance
or
Power = force * Velocity

EDIT: Sorry I keep getting interrupted here.

The definition of efficiency is...

Efficiency(%) = 100 * Energy out / Energy in

Rearrange to give Energy In..

Energy In = 100 * Energy Out/Efficiency

substitute force * distance for Energy Out

Energy In = 100 * force * distance/ Efficiency
 
Last edited:
thanks you!
 

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