Ok, so I'm trying to plot the unit circle using the chebyvhev metric, which should give me a square. I am trying this in MATLAB, using the 'pdist' and 'cmdscale' functions. My uber-complex code is the following: clc;clf;clear all; boundaryPlot=1.5; % Euclidean unit circle for i=1:360 theta(i)=deg2rad(i); end zc=[cos(theta)' sin(theta)']; % Transform to Chebychev metric x=zc(:,:); D=pdist(x,'chebychev'); D1=squareform(D); y=cmdscale(D1); % Plots hold on plot(y(:,1),y(:,2)); axis square;axis([-boundaryPlot boundaryPlot -boundaryPlot boundaryPlot]) plot([-boundaryPlot boundaryPlot],[0 0],'k') plot([0 0],[-boundaryPlot boundaryPlot],'k') where the part in bold is the really important part of the code. I have two problems with this. First, the 'y' variable which is supposed to hold the coordinates under the new metric has a size of 360x180. One of these dimensions should have been 2, which is the dimension of the L-p space (p=2). My second problem is that I get the plot you can see in the attachment, which corresponds to the Manhatan metric, and has rounded edges for some reason. Has anyone done this calculation before? Is there some other syntax/function I should be using??