Poisson distribution having variation coefficient = .5?

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Discussion Overview

The discussion revolves around the properties of the Poisson distribution, specifically focusing on the relationship between the mean, variance, and the variation coefficient. Participants explore the implications of these relationships and clarify definitions related to the Poisson distribution.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant states that the variation coefficient is calculated based on the relationship between mean and standard deviation, asserting that for a Poisson distribution, the mean equals the standard deviation.
  • Another participant proposes that the mean is equal to the variance, suggesting a different interpretation of the relationship.
  • A subsequent reply challenges the previous assertion by emphasizing that the defining property of a Poisson distribution is that the mean equals the standard deviation, not the variance.
  • One participant confirms the property of the Poisson distribution, stating that the mean is indeed equal to the variance.
  • A later reply acknowledges a misunderstanding regarding the distinction between variance and standard deviation, indicating a correction in their earlier reasoning.

Areas of Agreement / Disagreement

Participants express disagreement regarding the relationships between mean, variance, and standard deviation in the context of the Poisson distribution, with some clarifying definitions while others challenge the interpretations presented.

Contextual Notes

There are unresolved distinctions between variance and standard deviation, and the implications of these definitions on the properties of the Poisson distribution remain unclear.

Addez123
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TL;DR
How is it possible for a variation coefficient of poisson distribution to be anything other than 1?
Variation coefficient is calculated by
1608646163932.png

And the very definition of poisson distribution is that
$$\mu = \sigma $$

So how would any other value but 1 be a possible?
 
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μ = σ2
 
gleem said:
μ = σ2
Then its no longer a poisson distribution because the very definition of a poisson distribution is that
μ = σ, not μ = σ2
 
  • Skeptical
Likes   Reactions: pbuk
For a Poisson distribution, the mean is equal to the variance. Check your source.
 
  • Like
Likes   Reactions: Addez123 and pbuk
I see what I did wrong. I mixed up variance and standard deviation.
 

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