Pole Vaulting Kinematics Problem

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The pole vaulter leaves the ground with an initial speed of 9.5 m/s, reaching a speed of 7.1 m/s at 2.0 m above the launch point and taking 0.2 seconds to reach that height. The discussion highlights confusion around why there are two possible answers for the time taken to reach this height. It is clarified that one answer corresponds to the ascent and the other to the descent, as the pole vaulter must return to the same height after reaching the peak. The kinematic equations used can yield both solutions depending on the context of the motion. Understanding this duality is essential for solving similar problems in kinematics.
physicsnobrain
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Homework Statement


A pole-vaulter leaves the ground with an upward speed of 9.5 m/s.
(a) How fast is she going when she is 2.0 m above the launch point?
(b) How long is required to reach this height?
(c) Why are there two answers to (b)?



The Attempt at a Solution



Question A and B I don't have a problem with. I worked out A to be 7.1 m/s (2 sig digs) and B to be 0.2 seconds (2 sig digs).

However it is question C I am not understanding. I feel tempted to write "because I can write the answer in seconds or I can write it in minutes". But I feel this is a silly answer, therefore I need help.
 
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physicsnobrain said:
However it is question C I am not understanding. I feel tempted to write "because I can write the answer in seconds or I can write it in minutes". But I feel this is a silly answer, therefore I need help.
When the pole vaulter goes up, she must come down.
 
CAF123 said:
When the pole vaulter goes up, she must come down.

So there could be one answer that measures her going up and one answer that measures her going up then coming down?
 
physicsnobrain said:
So there could be one answer that measures her going up and one answer that measures her going up then coming down?
Yes, depending on what kinematic equation you use you will either get the two solutions automatically or not.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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