Undergrad Polynomial Division: Solve with Mike's Help!

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Mike sought help with polynomial division in his digital control systems course, specifically for the expression C(z) = (0.3678z + 0.2644) / (z^2 − 1.3678z + 0.3678). Initially, he struggled with long division due to confusion over the powers of the numerator and denominator. After receiving guidance, he realized that long division was indeed applicable and identified his mistake in interpreting the terms. Ultimately, he corrected his approach and achieved the desired result, which resembled a power series.
MikeSv
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Hello everyone.

Iam working on a course in digital control systems and by reading my textbook I stumbled over this expression.

C(z) = 0.3678z + 0.2644 : z^2 − 1.3678z + 0.3678
= 0.3678z^−1 + 0.7675z^−2 + 0.9145z^−3 + ...

Now Iam wondering how the result of the polynomial division is obtained?

I tried long division but I am not able to get the same result.

Any help would be great.

Thanks in advance,

Mike

Ps. Sorry for not using the editor as Iam writing from a. Mobile device
 
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MikeSv said:
I tried long division but I am not able to get the same result.
Hi Mike:

I think long division is the right approach. It might help me help you if you would show the details of the long division you did.

Regards,
Buzz
 
Hi again and thanks for your reply.

I just looked at the factional again and now Iam not sure anymore if long division works as the power of the denominator is higher than the power of the numerator.

Cheers,

Mike
 
MikeSv said:
Hi again and thanks for your reply.

I just looked at the factional again and now Iam not sure anymore if long division works as the power of the denominator is higher than the power of the numerator.

Cheers,

Mike
Yes, it still works. The first term of the dividend (the thing being divided) is .3678z, and the first term of the divisor is z2, so the first term in the quotient will be .3678*##\frac 1 z## or .3678z-1. Just continue the process as usual for polynomial division.
 
Hello again and thanks for all the replies.

I finally found my mistake.

I took z^-2 instead of z^2 in The second term:-(

Now I have the correct result which looks like a power series.

Thanks again,



Mike
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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