Polynomial roots & Mathematical induction

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Homework Help Overview

The discussion revolves around proving a recursive relationship involving the roots of a polynomial equation, specifically focusing on the expression S(n) = -p(S(n-2)) - q(S(n-3)) for n > 3, where S(n) is defined as the sum of the n-th powers of the roots.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship by manipulating the polynomial equation and calculating initial values for S(n). There is uncertainty about how to formally prove the relationship holds for n > 3.

Discussion Status

Some participants suggest that the recursive relationship can be derived from the polynomial equation without needing to calculate initial values. Others express concern about the necessity of proving the relationship specifically for n > 3, while noting that the problem does not explicitly require proving it does not hold for n ≤ 3.

Contextual Notes

There is mention of potential complications if p and q are both zero, indicating a special case that may need further consideration.

ben9703
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hi i have this homework question and I am not sure if my thought process is valid.

The Question:

let a, b and c be roots of the polynomial equation: x^3+px+q=0 and S(n)=(a^n)+(b^n)+(c^n)

now prove: that for S(n)= -p(S(n-2))-q(S(n-3)) for n>3my attempt:
-------------

first off i just played around with the equation. S(1)=0 , S(2)=-2p , S(3)=-3q after this all following values can be found by rearranging the polynomial to... x^3=-px-q and multiplying through x for each successive value of n. from this its clear how the above function ( S(n)= -p(S(n-2))-q(S(n-3)) ) arises. what I am not sure about is the pure mathematical proof to proving this (n>3).

if anybody could shine some light on the question or just share ideas i would be very grateful. Thanks :)
 
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ben9703 said:
hi i have this homework question and I am not sure if my thought process is valid.

The Question:

let a, b and c be roots of the polynomial equation: x^3+px+q=0 and S(n)=(a^n)+(b^n)+(c^n)

now prove: that for S(n)= -p(S(n-2))-q(S(n-3)) for n>3


my attempt:
-------------

first off i just played around with the equation. S(1)=0 , S(2)=-2p , S(3)=-3q after this all following values can be found by rearranging the polynomial to... x^3=-px-q and multiplying through x for each successive value of n. from this its clear how the above function ( S(n)= -p(S(n-2))-q(S(n-3)) ) arises. what I am not sure about is the pure mathematical proof to proving this (n>3).

if anybody could shine some light on the question or just share ideas i would be very grateful. Thanks :)

I think you are already done. ##x^n=-px^{n-2}-qx^{n-3}##, by multiplying your relation through by powers of x. So summing over a,b,c gives you S(n)=-p(S(n-2))-q(S(n-3)). I'm not even sure you needed to find those initial values, unless you actually want to calculate the values of S(n) using the recursion.
 
Yeah that's what I was thinking but I'm still not sure how to prove the domain n>3 . thanks for the reply
 
ben9703 said:
Yeah that's what I was thinking but I'm still not sure how to prove the domain n>3 . thanks for the reply

I don't think you need to worry about that. The problem just says to show it works if n>3. It doesn't say you have to show that it doesn't work for n<=3. Though if p=q=0 you might have a problem with that case.
 
Ah yeah I think your right. Thanks for answering when no one else did :)
 

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