A population has two alleles, B and b. the allele frequency of B is 0.73. what is the heterozygotes frequency, if the population is in H-W equilibrium?
two major important equations for Hardy-Weinberg:
p + q = 1
and p^2 + 2pq + q^2 = 1
You know 'p' in your problem: it is .73 Therefore you must know that 'q' is .27
since you know p = .73 and q = .27 you can find 2pq (which is the heterozygote frequency)
{Moderator edit: remainder of solution deleted. The student can solve from here on their own.}[/color]