- #1
Position and acceleration graphs
- Thread starter dlee9
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- Acceleration Graphs Position
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SUMMARY
The discussion focuses on deriving position and acceleration graphs from given velocity graphs in a physics context. It is established that the acceleration graph cannot be represented by option F, as the slope of the velocity curve remains consistent without abrupt changes. Additionally, the position graph is incorrectly represented by option I, since it indicates a negative slope at t=7, which contradicts the expected behavior of the velocity graph.
PREREQUISITES- Understanding of kinematics, specifically the relationships between position, velocity, and acceleration.
- Familiarity with graph interpretation in physics.
- Knowledge of calculus concepts, particularly derivatives as they relate to slopes of curves.
- Experience with graphing tools or software for visualizing motion graphs.
- Study the principles of kinematics in depth, focusing on the relationships between position, velocity, and acceleration.
- Learn how to calculate derivatives to analyze the slopes of velocity and position graphs.
- Explore graphing software such as Desmos or GeoGebra to visualize motion graphs effectively.
- Review common mistakes in interpreting motion graphs to enhance accuracy in problem-solving.
Students studying physics, educators teaching kinematics, and anyone interested in mastering graph interpretation in motion analysis.
- #2
- #3
CWatters
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I think you should check the first and last answers..
The graph for ax cannot be F. Acceleration is the slope of the velocity curve. At no point does the slope of the velocity curve change abruptly.
The graph for the position x cannot be I. At t=7 the slope of the position graph I is negative so the velocity should be negative.
The graph for ax cannot be F. Acceleration is the slope of the velocity curve. At no point does the slope of the velocity curve change abruptly.
The graph for the position x cannot be I. At t=7 the slope of the position graph I is negative so the velocity should be negative.
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