Position and acceleration graphs

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dlee9
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Homework Statement


Find the position and acceleration graphs from the velocity graphs given.

Homework Equations

The Attempt at a Solution


I'm pretty sure I've gotten some of them correct but I don't know which one I've done wrong.
 
Attachments
  • Two labelled sketch graphs, A and B, with time in seconds from 0 to 16 on the horizontal axis and a level marked 0 on the vertical axis; graph A is a piecewise curve and graph B is a piecewise step-like curve.
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  • Three labelled line graphs C, D and E, each plotting a quantity against time in seconds from 0 to 16 with a horizontal zero line and dotted grid lines.
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  • Three stacked graphs labelled F, G and H, each plotting a quantity against time in seconds from 0 to 16 with a horizontal line at 0; F is a piecewise curve with steps, G a smooth hump curve, H a step function.
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  • Three stacked graphs labelled I, J and K, each plotting a curve against time in seconds from 0 to 16 with a dashed zero line on the vertical axis.
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  • Three stacked graphs labelled L, M and N, each plotting a quantity against time in seconds from 0 to 16, with a dotted zero line on the vertical axis.
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  • Four dropdown answer rows: graph closest to a_x is F; graph closest to v_y is C; graph closest to a_y is H; graph closest to x is I.
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here are the velocity graphs given
 
Attachments
  • Two velocity-time graphs stacked vertically: top shows x velocity, a smooth curve rising from below zero to a peak near 7 s then falling below zero by 16 s; bottom shows y velocity, a line falling to a flat segment from about 5 to 9 s, then rising to a peak near 12 s and falling to 16 s. Time axis 0 to 16 seconds.
    graph.PNG
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I think you should check the first and last answers..

The graph for ax cannot be F. Acceleration is the slope of the velocity curve. At no point does the slope of the velocity curve change abruptly.

The graph for the position x cannot be I. At t=7 the slope of the position graph I is negative so the velocity should be negative.
 
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