Position and acceleration vector - parallel and perpendicular

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The discussion revolves around determining the conditions under which the position vector and acceleration vector of a particle are parallel or perpendicular, based on the given position vector equation. The proposed method involves differentiating the position vector twice to find the acceleration vector and then using the dot product for perpendicularity and the cross product for parallelism. However, some participants question the validity of the position vector, suggesting it may not yield real values of t where the vectors are parallel or perpendicular. Despite these concerns, the original problem is presented as part of a university exam. The conversation highlights the importance of verifying the correctness of the initial equations in vector analysis.
logearav
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Position and acceleration vector -- parallel and perpendicular

Homework Statement



The motion of a particle is defined by the position vector
r = A(Cos t + t Sin t) i + A(Sin t + t Cos t) j where t is expressed in seconds. Determine the values of t for which the position vector and acceleration vector are
a) perpendicular
b) parallel

Homework Equations




The Attempt at a Solution


For acceleration i have differentiate r twice and arrive at the equation. So, i should go for cross product to find 't' when they are parallel and dot product when they are perpendicular.
Am I right in my procedure, revered members?
 
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logearav said:

Homework Statement



The motion of a particle is defined by the position vector
r = A(Cos t + t Sin t) i + A(Sin t + t Cos t) j where t is expressed in seconds. Determine the values of t for which the position vector and acceleration vector are
a) perpendicular
b) parallel

Homework Equations




The Attempt at a Solution


For acceleration i have differentiate r twice and arrive at the equation. So, i should go for cross product to find 't' when they are parallel and dot product when they are perpendicular.
Am I right in my procedure, revered members?

Your proposed method looks fine, but is the given position vector correct? It doesn't appear to me that the position and acceleration vector will ever be perpendicular or parallel for a real value of t.
 


Thanks gneill. But this is how the question appears in University Exam paper.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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