- #1
Loppyfoot
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Homework Statement
A particle moves in the xy plane with constant acceleration. At t = 0 the particle is at rvec1 = (3.7 m)i + (3.4 m)j, with velocity vvec1. At t = 3 s, the particle has moved to rvec2 = (9 m)i − (1.9 m)j and its velocity has changed to vvec2 = (5.4 m/s)i − (6.5 m/s)j. (a) Find vvec1.(b) What is the acceleration of the particle?(c) What is the velocity of the particle as a function of time?(d) What is the position vector of the particle as a function of time?
I need some guidance. I tried using the average velocity formula for (a), but it doesn't seem to be working for me. I tried doing 9-3.7 / 3. for the i vector. And likewise, for the j vector (-1.9-3.4)/3. I get 1.76i-1.76j, and it isn't correct.
I need some guidance on the others too. Thanks guys.