Acceleration between two frames

[PeroK]

I do not disagree either with you or with @haruspex. All I am pointing out is that since the statement of the question does not exclude my example explicitly, choice (d) must be True in that case also. True means True in all scenarios that match the parameters of the problem else the parameters need to be sharpened, in this case by saying that the accelerations are in straight lines that could form any angle between them.

Sorry, that's absurdist logic. If someone has a British coin, say, then it could be anything from 1p to £2. That's the answer - it could be anyone of those. If you have a 5p piece, you can't declare that to be an exception to the rule - because it's only one of the possibilities and not them all simultaneously.

 

[kuruman]

I don't think I explained my point in a way that can be understood. I will have to rethink how to go about it.

 

[Orodruin]

I don't think I explained my point in a way that can be understood. I will have to rethink how to go about it.

The problem is that you have picked a particular case of the possible cases. Based only on the information in the problem, there are other cases that would satisfy the other values. The question is about what values are possible given the information given, not a particular case.

 

[Orodruin]

then it could be anything from 1p to £2

I’d like a $\pi$ pence coin, please. ;)

 

[Monsterboy]

Both diagrams are wrong. You made the same mistake earlier in the thread. See posts 5 through 9.

That said, your reasoning about the range of magnitudes of $\vec a_{S1,S2}$ is correct.

I'll add that you really shouldn't need us to confirm the correctness of your answers. You need to construct your understanding so that you can be reasonably confident on your own that an answer is correct, not relying one some authority to tell you that.

I haven't studied physics since 2010 and that was just basic stuff, so anything I think is correct is probably not.
Anyway, I hope the below is correct.

 

[vela]

Both diagrams are wrong. You made the same mistake earlier in the thread.

I haven't studied physics since 2010 and that was just basic stuff, so anything I think is correct is probably not. Anyway, I hope the below is correct.

We all make mistakes, so it's important to develop the ability to check your work and find those mistakes. For example, when you drew the first diagram, you could have also written down the equation it represents by interpreting the diagram. Then you would have hopefully seen the subscripts were messed up and realized the diagram had a problem. By getting in the habit of looking at the same concept in different ways, you'll start to see how they all fit together.

View attachment 291185

The second diagram is still wrong.

 

[Monsterboy]

The second diagram is still wrong.

Ok, when I tried parallelogram, I figured I was putting $-\vec{a}_{P, S2}$ on the wrong side.

This must be right.

 

[vela]

That's right.

 

[Monsterboy]

Thanks all, for the support!