- #1
JJfortherear
- 14
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I've been told this is a differential equation, but I have no knowledge of the subject, so I'm hoping it is and that an answer can be found in this forum. The two equations x=1/2at2 and a=gm/r2, when r is replaced with (r0-x), with r0 being the initial radius from the mass from which the gravitational field originates, and x being the distance traveled since t=0, due to the acceleration of the field. Combining these equations gives
x=1/2(gm/(r0-x)2)t2
I don't know how to solve that equation for x, and I'm hoping this is the place to look for help. Thanks.
x=1/2(gm/(r0-x)2)t2
I don't know how to solve that equation for x, and I'm hoping this is the place to look for help. Thanks.