Position in Velocity-Time Graphs

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Multiplying time by velocity gives the change in position when velocity is constant, as the units cancel to meters. For example, multiplying 2 seconds by 1 m/s results in a position change of 2 meters. This method is valid for calculating displacement in uniform motion. Additionally, the area under a velocity-time graph represents the total displacement, with negative areas indicating movement in the opposite direction. Understanding these concepts is crucial for analyzing motion in physics.
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Homework Statement
How do I find the position of an object in a velocity-time graph?
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Would it be correct if I multiplied the time by the velocity of the object since the units would cancel into meters? So for example, I multiply 2 seconds by 1m/s which gives me 2m - would that be the object's position?
 
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If the velocity is constant, that will give you the change in position.
More generally, take the area under the curve (counting as negative where the velocity is negative).
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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