- #1

Spooky123

- 3

- 0

- Homework Statement
- You walk in the direction of the unit vector <1,0, 0> a distance of214 m at a constant speed of 3.6 m/s, then turn and walk in the direction of the unit vector <1, 0, 1>/ root 2 for a distance of 16 m at a constant speed of 3 m/s. What was your average velocity?

- Relevant Equations
- Vavg = delta r / delta t

I know that average velocity is the change in position over the change in time. But im getting conflicting views from other sources saying thats its the total distance divided by the total time. For this question we would first find the respective vectors by multiplying the distance with the given unit vectors. Then according to the average velocity formula we would find the difference between both vectors (change in position). To find the respective times, we would use the distance divided by the speed given for each. Using the final formula for avg velocity should give us the answer.

R1 = <21,0,0>m

R2 = <11.31,0,11.31>m

Delta R = R2 - R1

= <-9.69,0,11.31>

t1 = d1/v1 = 21/3.6 = 5.833

t2 = d2/v2 = 16/3 = 5.33

Delta t = t2 - t1 = -0.5

Thus, Average velocity = Delta R / Delta T?

Is this the right way to go about it?

R1 = <21,0,0>m

R2 = <11.31,0,11.31>m

Delta R = R2 - R1

= <-9.69,0,11.31>

t1 = d1/v1 = 21/3.6 = 5.833

t2 = d2/v2 = 16/3 = 5.33

Delta t = t2 - t1 = -0.5

Thus, Average velocity = Delta R / Delta T?

Is this the right way to go about it?