Position of a particle is given by x = (2 cm) cos 10πt

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SUMMARY

The position of a particle is defined by the equation x = (2 cm) cos 10πt. The frequency of the motion is 5 Hz, derived from the angular frequency ω = 10π rad/s. The period of the motion is 0.2 seconds, calculated as T = 1/f. The amplitude of the particle's motion is 2 cm, and the first time the particle reaches its equilibrium position after t = 0 is at 0.1 seconds, moving in the positive direction.

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Homework Statement



The position of a particle is given by x = (2 cm) cos 10πt, where t is in seconds.
(a) What is the frequency?
Hz
(b) What is the period?
s
(c) What is the amplitude of the particle's motion?
cm
(d) What is the first time after t = 0 that the particle is at its equilibrium position?
sIn what direction is it moving at that time?
in the negative direction
in the positive direction

Homework Equations





The Attempt at a Solution

 
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The general form of the equation you are using is
x = ACos(ωt)
x is the displacement, A is the amplitude and ω is the ANGULAR frequency
Hope this helps
 


You will need to show some working first, where are you having problems and what have you done so far?
 

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