Bolter
- 262
- 31
- Homework Statement
- Calculate the velocity of a particle moving in SHM at a point
- Relevant Equations
- a = –w^2x
So the way I have gone about it is to assume that the equilibrium position is half way between the 2 end points, hence the amplitude of this motion is 9.3/2 = 4.65 cm
Therefore the displacement of the particle when it is 2cm away from one end point should be the distance between that point and the equilibrium position. So i.e. 4.65 – 2 = 2.65 cm
Knowing those 2 values I have done this
Is a speed of 0.16 m/s be what you should get?
Thanks for any help!